**Answer:**

**Q = 6.33μC**

**Explanation:**

To find the value of the charge Q you take into account both gravitational force and electric force over each ball. By symmetry you can use the fact that both balls experiences the same forces. Hence you only take into account the forces for one ball for the x component and y component:

M: mass of the ball = 0.09kg

T: tension of the string

F_e: electric force between charges

angle = 45°

The electric force is given by:

Q: charge of the balls

r: distance between balls = 2m

You divide both equation in order to eliminate the tension T:

By doing Q the subject of the formula and replacing you obtain:

**hence, the charge of the balls is 6.33μC**

**Answer:**

B = 2.9 mT

**Explanation:**

Given that,

The distance between the wires, r = 2 cm

Distance halfway between them d = 1 cm = 0.01 m

The current in the wires, I = 145 A

We need to find the strength of the magnetic field they produce, halfway between them. The formula for the magnetic field in the wire is given by :

**So, the required magnetic field is 2.9 mT.**

Standard sea level pressure by definition equals 760 mm (29.92 inches) of mercury

**Answer:**

SORRY NOONE CAN HELP YOU>>> YOU OUR A LOST CAUSE

**Explanation:**

sorry the photo is blocked on my computer, but that doesnt mean your a lost cause..... have a good day

**Answer:**

dont have the answer but you cute

**Explanation:**